a ball of mass 500 g kept near the earth's surface will attract the earth with a force of
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Answered by
1
there will be only gravitAtional force action on the ball
thus F= 500g×10m/s^2
5000×10^-3
gives us 5N
hope this will help u bro
thus F= 500g×10m/s^2
5000×10^-3
gives us 5N
hope this will help u bro
Answered by
4
Hey there!
We know,
F = mg
where,
F = force
m = mass
g = gravitational constant (9.8 m/s^2)
ATQ,
mass = 500 g = 0.5 kg
gravitational constant = 9.8 m/s^2
Put the values:
F = mg
F=0.5 * 9.8
F=4.90 Newton
Hope it helps you!
We know,
F = mg
where,
F = force
m = mass
g = gravitational constant (9.8 m/s^2)
ATQ,
mass = 500 g = 0.5 kg
gravitational constant = 9.8 m/s^2
Put the values:
F = mg
F=0.5 * 9.8
F=4.90 Newton
Hope it helps you!
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