a ball of mass 500g is thrown vertically upward and reaches a height of 5m find its initial momentum (take acceleration to be 10m/s^2)
Answers
Answer:
Mass of the object : 500g=0.5 kg=m
Height,s =5 m
Acceleration due to gravity=10 m/s^2=a
Initial velocity of object(from point where it is dropped=0m/s=u
Therefore, we need to find final velocity of object, so here we go
According to motion formula,
2as=v^2-u^2
2as+u^2=v^2
(2×5×10)+(0×0)=v^2
√100=v
v=10 m/s
Now, momentum=velocity ×mass
=0.5×10=5 kg m/s
Hence the momentum of the object when it hits the floor will be 5 kg m/s.
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Answer:
Any object of mass 500g is dropped from a tower of height 5m. How would you calculate its momentum when it touches the ground?
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Mass of the object : 500g=0.5 kg=m
Height,s =5 m
Acceleration due to gravity=10 m/s^2=a
Initial velocity of object(from point where it is dropped=0m/s=u
Therefore, we need to find final velocity of object, so here we go
According to motion formula,
2as=v^2-u^2
2as+u^2=v^2
(2×5×10)+(0×0)=v^2
√100=v
v=10 m/s
Now, momentum=velocity ×mass
=0.5×10=5 kg m/s
Hence the momentum of the object when it hits the floor will be 5 kg m/s.