Question

A ball of mass 500gm moving with a speed of 10m/s rebounds after striking normally a perfectly elastic wall. find the change in momentum of the ball. if contact time with the wall is 0.1 second, what force is exerted by the wall?

Answer 1

momentum = product of mass and velocity

                   =500×10

momentum =5000 kg m/s

f=ma

f=m$\frac{v-u}{t}$

f=500$\frac{0-10}{0.1}$

f=500$\frac{-10}{0.1}$

f=$\frac{-5000}{o.1}$

f=-50000N

Answer 2

Answer:

$</p><p></p><p>\huge \bf \underline \purple{❥} \underline \red{A} \underline \orange{n} \underline \pink{s} \underline \green{w} \underline \blue{e} \underline \orange{r} \red{:⇢}$

your answer in attachment..