a ball of mass 50g is thrown vertically upward with a speed of 20m/s calculate a.maximum height attained. by) time taken to reach the highest point . take g= 10m/s^2
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initial velocity ( u)=20 m/s
final velocity (v) =0
(As velocity of the object at highest point is always zero)
acceleration (g)=10 m/s
v² = u ² + 2 as
v² = u² - 2 g h
u² = 2 g h
h = u²/2 g
h= 400/20
h=20m
v= u+ at
v= u -gt
u= gt
t = u/g
t=20/10
t= 2 sec
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