Question

A ball of mass 5kg is vertically thrown upwards with intial velocity 20m/s what will be the k.e and p.e after 2 secs

Answer 1

Answer:

Explanation:

total height traveled in 2 secs

=20*2 =40 m

P.E = mgh

=5*10*40

=2000J

K.E.=1/2MV^2

=1/2*5*20^2

=1/2*5*400

=200*5

=10000J