A ball of mass 600 gm strikes a wall with a velocity of 5 ms at an angle 30 with the wall and rebounds with the same speed at the same angle with the wall.the change in momentum of the ball is
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Let the ball strike the wall with velocity u =5m/s at an angle 30° with wall.Therefore angle of incidence=60°.Initial momentum along is normal -mucos60° .Final momentum along normal is mucos60°.Therefore change in momentum is =mucos60° -(-mucos60°).=2mucos60° =2×.6×4×.5=3Kgm/s.
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Answer:
the change in momentum of the ball is 3 kg ms^-1
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