Question

) A ball of mass 60g is moving due south with a speed of 50 ms−1

at latitude 30ºN.

Calculate the magnitude and direction of the coriolis force on the ball. Compare the

magnitude of this force to the weight of the ball

Answer 1

Answer:

Coriolis force is basically a pseuo force like centrifugal force which explains the effect on a rotating body with frame of reference as universe .....

For understanding this u have to accept that as earth is rotating ...ball will show 3 D motion

Explanation:CF =2*V*A*Sin (latitude)

Here V = wind velocity or we can say the velocity of ball (as wind will flow with an equal speed wrt the ball but in opposite direction)

A = Angular velocity of earth = MVR = 2*10^-7

Latitude is 30° as given in question

So C F = 2 *50*2*10^(-7)sin30

=> FORCE =10^(-6)Newton

Answer 2

Given:

A ball of mass 60g is moving due south with a speed of 50 ms−1  at latitude 30ºN.  

To find:

Calculate the magnitude and direction of the coriolis force on the ball. Compare the  magnitude of this force to the weight of the ball.

Solution:

From given, we have,

The mass of ball = 60 g = 0.06 kg

Speed of the ball = 50 ms-1

Latitude = 30ºN.

we use the formulae:

F_c = 2mwv sin α

F_g = mg

So, we have,

F_c = 2mwv sin α = 2 (0.06) (7.3 × 10^{-5}) (50) sin 30

∴ F_c = 21.5 × 10^{-5} N

The direction is to left of the motion in the Southern Hemisphere: toward east.

F_g = mg = 9.8

Now, we have the ratio:

F_c/F_g = 2mwv sin α/mg

= 2wv sin α/g

= [ 2 (7.3 × 10^{-5}) (50) sin 30 ] / 9.8

= 3.7 × 10^{-4}

∴ F_c/F_g = 3.7 × 10^{-4}