A ball of mass 6kg moving with a velocity of 10−1
collides with a 2kg ball in
opposite direction
With a velocity of 5−1
. After the collision the two balls coalesce and move
in the same direction.
Calculate the velocity of the composite body
Answers
Answered by
1
m1= 6kg
u1= 10m/s
m2= 2kg
u2= -5m/s.
Before collision,
Momentum= m1u1 - m1u1
= (6)(10) - (2)(5)
= 60 - 10= 50kgm/s
After collision,
Momentum= (m1 + m2)V
= (6 + 2)V
= 8V
From the law of conservation of linear momemtum, the momentum before collision is equal to the momentum after collision.
50= 8V
V= 50/8= 6.25m/s.
Answered by
0
Answer:m1= 6kg
u1= 10m/s
m2= 2kg
u2= -5m/s.
Before collision,
Momentum= m1u1 - m1u1
= (6)(10) - (2)(5)
= 60 - 10= 50kgm/s
After collision,
Momentum= (m1 + m2)xV
= (6 + 2)xV
= 8V
The momentum before collision is equal to the momentum after collision.
50= 8V
V= 50/8= 6.25m/s.
Explanation:
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