Physics, asked by zainabnabeelah, 5 months ago

A ball of mass 6kg moving with a velocity of 10−1
collides with a 2kg ball in
opposite direction
With a velocity of 5−1
. After the collision the two balls coalesce and move
in the same direction.
Calculate the velocity of the composite body

Answers

Answered by lalitmandrai
1

m1= 6kg

u1= 10m/s

m2= 2kg

u2= -5m/s.

Before collision,

Momentum= m1u1 - m1u1

= (6)(10) - (2)(5)

= 60 - 10= 50kgm/s

After collision,

Momentum= (m1 + m2)V

= (6 + 2)V

= 8V

From the law of conservation of linear momemtum, the momentum before collision is equal to the momentum after collision.

50= 8V

V= 50/8= 6.25m/s.

Answered by ezegbudochukwudi
0

Answer:m1= 6kg

u1= 10m/s

m2= 2kg

u2= -5m/s.

Before collision,

Momentum= m1u1 - m1u1

= (6)(10) - (2)(5)

= 60 - 10= 50kgm/s

After collision,

Momentum= (m1 + m2)xV

= (6 + 2)xV

= 8V

The momentum before collision is equal to the momentum after collision.

50= 8V

V= 50/8= 6.25m/s.

Explanation:

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