A ball of mass falls vertically from a height h and collides with a block of equal mass m moving horizontally with a velocity v on the surface
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Answer:
Using impulse = change in linear momentum along vertical axis on ball Ndt =
where as on block : μNdt = mv – mv′
2×3/2√2gh×m
= m (v – v′)
∴ v – v′ =
3√2gh
Explanation:
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