A ball of mass is thrown with speed v towards Bat. It rebounds along the same speed. The variation of interaction force between
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Answer:
Area under the F-t graph gives the change in momentum of the body during that period.
∴ ΔP=
2
1
F
o
T
Also as the collision of ball with the wall is elastic, thus the ball colliding with the wall with initial speed v rebounds with the same speed u.
Thus the change in momentum of ball ΔP=mu−(−mu)=2mu
∴
2
F
o
T
=2mu ⟹F
o
=
T
4mu
Explanation:
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