Question

A ball of mass m and density p is immersed in a liquid of density 3p at a depth h and released. To what height up above the surface of liquid?

Answer 1

Explanation:

Mass =m

density = p

liquid density= σ

Height (depths)= h

Net upward force acting on the body; F=σvg−ρvg=ma

a=g(σρ−1)

velocity after height h; v=2g(σρ−1)h−−−−−−−−−√

conserving mechanical energy at max height h′ and at surface,

mgh′=12m(2g(σρ−1)h)

h′=(σρ−1)h