Question

a ball of mass m fall from height h on a floor of coefficient of restitution 0.5 the height attained by the ball after 2 rebound is

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Answer 1

Answer:

ANSWER

A ball falling from height h reaches the floors with velocity

v=

2gh

By definition

e=

velocity of approach

velocity of separation

∴ Rebound velocity =e

2gh

∴ Rebound height =e

2

h

After two rebounds, height=e

4

h

Answer 2

Answer:

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Explanation:

A ball falling from height h reaches the floors with velocity

v=

2gh

By definition

e=

velocity of approach

velocity of separation

∴ Rebound velocity =e

2gh

∴ Rebound height =e

2

h

After two rebounds, height=e

4

h.

hope it helped :-)