Question

A ball of mass ‘m’ falls vertically on the ground from a height ‘h’ and rebounds. If coefficient of
restitution between ball and ground is 1/2
then the magnitude of change in momentum of ball during collision with ground is

Answer 1

Explanation:

Velocity just before striking the ground will be velocity gained after falling a height h

1

so V

i

=

2gh

1

Velocity just after rebounding will be the velocity needed to gain a height h

2

so V

f

=

2gh

2

so change in momentum will be ΔP=mΔV=m(V

f

−V

i

)=m(

2gh

2

+

2gh

1

)