A ball of mass m hits a floor with a speed v making an angle alpha with the normal n
Answers
Answered by
0
Answer:
m hits a floor with a speed v making an angle a with the normal N. The ... The ball makes an angle α with the normal, its speed is v. Therefore, ... \implies \tan\theta=\frac{ev\cos\alpha}. \implies ... Mass of ball=m kg. Speed =V.
Explanation:
Answered by
1
Answer:
Velocity of approach in the given case is the normal component of velocity.
Hence, v
n
=vcosθ
By definition of coefficient of restitution, velocity of separation will be,
v
n
′
=ev
n
=evcosθ
Tangential component of velocity will not change.
v
t
′
=v
t
=vsinθ
Speed of reflected ball is:
v
′
=
v
n
2
+v
t
2
=
(evcosθ)
2
+(vsinθ)
2
=v
e
2
cos
2
θ+sin
2
θ
Angle with normal is given by:
θ
′
=tan
−1
v
n
′
v
t
′
θ
′
=tan
−1
(
evcosθ
vsinθ
)
θ
′
=tan
−1
(
e
tanθ
)
Similar questions