Question

A ball of mass m hitting the ground with velocity u ,bounces back with velocity v in a small time interval t , the force exerted on the ground is

2 points

m(v-u/t)

b) mv/t

c) mu/t

d) m(v+u/t)​

Answer 1

Answer:

m(v-u/t)

Step-by-step explanation:

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Answer 2

The force exerted on the ground is m (v/t).

• Force is the external agent that changes the state of rest or of uniform motion of a body.
• It is given by the formula,

       $F = ma$

• Here, F is the force exerted on the ground, m is the mass of the ball and a is the acceleration of the ball.
• Acceleration is given by the formula,

        $a = \frac{v}{t}$

• Here, v is the velocity of the ball and t is the time interval.
• On adding the value of acceleration in the force formula,

        $F = m \frac{v}{t}$