a ball of mass m is dropped from the height h and strikes the ground with kinetic energy 1/3 mgh. the work done by resistance is
Answers
Given info : a ball of mass m is dropped from the height h and strikes the ground with kinetic energy 1/3 mgh.
To find : The work done by resistance is ...
solution : initial velocity of ball, u = 0 [ because ball has dropped ]
so initial kinetic energy of ball = 0
initial potential energy of ball = mgh
so total mechanical energy of ball = mgh + 0 = mgh
after striking the ground,
kinetic energy of ball = 1/3 mgh
potential energy of ball = 0 [ because height of ball from the ground is zero ]
so total mechanical energy = 1/3 mgh + 0 = 1/3 mgh
from Work energy theorem,
change in mechanical energy = work done by resistance on ball
⇒mgh - 1/3 mgh = work done by resistance
⇒work done by resistance = 2/3 mgh
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