Question

A ball of mass M is projected from ground with velocity U at an angle theta with the horizontal the angular momentum of the Bal about the point of projection , at time is​

Answer 1

here's your answer. hope this helps....

Answer 2

Answer:

Angular momentum is m.v.r.sin(theta)

Explanation:

Angular momentum of a projectile at the top most point is

m x v x r x sin(theta)  = m ucos(theta). H