Question

A ball of mass 'm' is thrown at an angle of ' θ ' with the horizontal with an initial velocity 'u'. The change in its momentum during its flight in a time interval of’t’ is
1) mgt
2) mgt cosθ
3) mgtsinθ
4) 1/2 mgt

Answer 1

4-1/2mgt

We know that,

v−u=−gt⟹u−v=gt→(1)

multiply with m.

mu−mv=mgt

Change in its momentum=mgt

Where=U=usinθ

No matter any value.