a ball of mass m is thrown at an angle theta with the horizontal with an initial velocity u. The change in its momentum during its flight, in a time interval of t is
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Answer:
We know that,
v−u=−gt⟹u−v=gt→(1)
multiply with m.
mu−mv=mgt
Change in its momentum=mgt
Where=U=usinθ
No matter any value.
Explanation:
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