Question

a ball of mass m is thrown up vertical . another ball of mass 2m is thrown at an angle with thre vertical.both of them stay in air for same period of time.what is ratio of high attained by two balls

​

Answer 1

Answer:

They both attain the same height because they both must have

equal vertical components of velocity.

H = 1/2 g t^2    where t is the time to fall a distance H

Also, H = Vy t - 1/2 g t^2

Vy - g t = 0     where t is time for vertical velocity to reach zero

t = Vy / g

So H = Vy^2 / g - 1/2 g * Vy^2 / g^2 = Vy^2 / (2 g) = 1/2 g t^2

Showing the time to rise to height H is the same as the time to fall H