a ball of mass m is thrown vertically upward another ball of mass 2m is thrown making an angle theta if there times of ascent are same then the ratio of their heights attained
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Hi..
H1=U1^2/2g
H2= U2^2.SinO^2/2g
T1=2U1/g
T2= 2U2SinO/g
Given T1=T2
Therefore 2U1/g=2U2SinO/g or U1 = U2 SinO
H1= U1^2/2g = (U2 SinO)^2 /2g = U2^2.SinO^2/2g = H2
Therefore H1/H2 = 1:1 (Ans)
Hope this helps u!!
H1=U1^2/2g
H2= U2^2.SinO^2/2g
T1=2U1/g
T2= 2U2SinO/g
Given T1=T2
Therefore 2U1/g=2U2SinO/g or U1 = U2 SinO
H1= U1^2/2g = (U2 SinO)^2 /2g = U2^2.SinO^2/2g = H2
Therefore H1/H2 = 1:1 (Ans)
Hope this helps u!!
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