A ball of mass m is thrown vertically upward from the ground and reaches a height h before momentarily coming to rest. If g is acceleration due to gravity, what is the impulse received by the body due to gravity for
ce during its flight? (Neglect air resistance)
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Answer:
Explanation:
Impluse=change
in momentum
DeltaP=mv-mu=mv-m (-v)=2mv
Maximum height h=vsquare/2g
Vsquare=2gh v=root2gh
Impulse=2mroot2gh=root4msquare (2gh )
Impulse =root8msquaregh
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