A ball of mass 'm' moving horizontally with velocity 'u' along positive x direction , strikes a wall for a very small time interval 't' and rebounds back with same speed along the same path. The ball experiences force which is equal to _____________ in ________________direction
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Answer:
mass = m
initial velocity = u (constant)
time = t
therefore, acceleration = u/t ( constant velocity)
force = m×a
= um/t N
hence force on object = um/t Newton in 'x' direction which is perpendicular to the wall.
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