Question

A ball of mass M moving with speed v collides
perfectly inelastically with another ball of mass m
at rest. The magnitude of impulse imparted to the
first ball is

(1) Mv

(2) mv

$(3) \: (\frac{Mm}{M + m}) v$

$(4) \: ( \frac{ {M}^{2} }{M + m})v$

Answer with proper calculation!!

Answer 1

I think option (3) is correct .

Answer 2

RA71

the collision is perfectly inelastic
Both of'em will stick together!
Then,

V = velocity of the combined mass.

Therefore,

mv = (M + m)V
V = (m/M+m)v

Impulse imparted to the 1st ball will be

MV = MmV / m+M

^_^_^