A ball of mass m moving with velocity v collides head on with the second ball of mass m at rest. If the coefficient of restitution is e and velocity of first ball after collision is v1 and velocity of second ball after collision is v2 then
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Answered by
89
Hii friend,
# Complete question should be-
The first ball of mass m moving with a velocity v collides head on with the second ball of mass m at rest.If the coefficient of restitution is e,then what is the ratio of the velocities of the first and the second ball after the collision?
# Answer-
v1/v2=(1-e)/(1+e)
# Explanation-
Let,the 1st ball will move with a velocity of v1 and the 2nd one with v2 after the collision.
By law of conservation of momentum
mv+m.0=mv1+mv2
v=v1+v2 ...(1)
In this case coefficient of restitution
e=(v2-v1)/v
ev=v2-v1 ...(2)
Solving (1) & (2)
v1=v(1-e)/2
v2=v(1+e)/2
v1/v2=(1-e)/(1+e)
Hope this is useful...
# Complete question should be-
The first ball of mass m moving with a velocity v collides head on with the second ball of mass m at rest.If the coefficient of restitution is e,then what is the ratio of the velocities of the first and the second ball after the collision?
# Answer-
v1/v2=(1-e)/(1+e)
# Explanation-
Let,the 1st ball will move with a velocity of v1 and the 2nd one with v2 after the collision.
By law of conservation of momentum
mv+m.0=mv1+mv2
v=v1+v2 ...(1)
In this case coefficient of restitution
e=(v2-v1)/v
ev=v2-v1 ...(2)
Solving (1) & (2)
v1=v(1-e)/2
v2=v(1+e)/2
v1/v2=(1-e)/(1+e)
Hope this is useful...
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17
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