A ball of mass m moving with velocity v strikes the bob of a pendulum at rest. The mass of the bob is also
If the collision is elastic, the height to which the bob will rise will be?
please answer it correctly
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Answer:
2
V
8g
Explanation:
From conservation of linear momentum before and after the collision,
mv=(m+m)v′
⟹v′ = v/2
All the initial kinetic energy gets converted to gravitational potential energy at the maximum height.
Thus, 1 (2m) v′2 =(2m)gh
2
⟹h = v2
8g
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