Physics, asked by Robingautam, 11 months ago


A ball of mass m travelling with velocity 2i+3j receives an impulse -3mi. What is the velocity of ball
immediately afterwards ?​

Answers

Answered by sonuvuce
2

Answer:

Velocity of the ball afterwards is -\hat i+3\hat j

Explanation:

Mass of the ball = m

Velocity of the ball = 2\hat i+3\hat j

The ball receives an impulse of -3m\hat i

If the velocity of the ball afterwards is \vec v

Then, using

\boxed{\text{Change in momentum}=\text{impulse recieved}}

or, \boxed{m(\vec v_f-\vec v_i)=J}

or, m[\vec v-(2\hat i+3\hat j)]=-3m\hat i

\implies \vec v-(2\hat i+3\hat j)=-3\hat i

\implies \vec v=-3\hat i+2\hat i+3\hat j

\implies \vec v=-\hat i+3\hat j

Therefore, velocity of the ball afterwards is -\hat i+3\hat j

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