a ball of mass mass m kg is thrown vertical upwards . another ball of mass 2m kg is thrown at angle X with the vertical. both stays in air for the same period the height reached are inthe ratio
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Explanation:
Time of flight in case (1) = case (2)
g2V1=g2V2sinθ⇒V1=V2sinθ
max height reacted by (1)=2gV12=H1
max height reacted by (2)=2g(V2sinθ)2=H2
⇒H1=H2.
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