Question

A ball of mass of 200g hits a wall at an angle of 45 degree with a velocity of 15 m/s .If the ball rebounds at 90 degree to the direction of incident,calculate the impulse received by the ball

Answer 1

When the ball hits the ball, it makes an angle of 45° with the wall. Similarly, It is also making an angle of 45° with the Normal.

∴ Initial Momentum of the body along the Horizontal = mvcos45°

= 0.2 × 15 × 1/√2 = 3/√2  (negtiave direction)

Final Momentum = mvcos45° = 3/√2 (positive direction)

∴ hnage in momentum = Final - Initial = 3/√2 - ( - 3/√2)

= 3/√2 + 3/√2

= 6/√2 = 3√2 Ns.

Since, change in momentum is Impulse, Therefore, Impulse = 3√2 Ns.

Hope it helps.