Question

A ball of radius 1 cm is put into a cylindrical pipe so that it fits inside the pipe. if length of pipe is 14m, what is the surface area of the pipe

Answer 1

Circumference of base of cylinder = 2π × 1

Now,

TSA of cylinder = 2πr(r+h)

= 2 × 22/7 × 1 (1+14000) ........(14m = 14000cm)

= 44/7 × 14001

= 88006.29 cm² ............★ANS★

______☺☺☺______

$HOPE \: IT \: WILL \: HELP \: YOU. . . . . . .$

Answer 2

Answer:

$0.880628 m^2$

Step-by-step explanation:

A ball of radius 1 cm is put into a cylindrical pipe so that it fits inside the pipe.

So, The radius of cylinder = 1 cm = 0.01 m

Length of pipe is 14 m

Total surface area of cylinder = $2\pi r h +2 \pi r^2$

Substitute the values

Total surface area of cylinder = $2 \times \frac{22}{7} \times 0.01 \times 14 +2\times \frac{22}{7} \times 0.01^2$

                                                 = $0.880628 m^2$

Hence the surface area of the pipe is $0.880628 m^2$