A ball of radius 11 cm and mass 8 kg rules from rest down the ramp of 2 metre the ramp is inclined at 35 degree to the horizontal when the ball reaches the bottom its velocity is
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apply law of conservation of energy
mgh = 1/2mv^2 + 1/2Iw^2 where W = V/R and I = 2/5MR^2
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