Question

A ball of the mass 20 gram is fired with velocity of hundred metre per second if mass of the gun is 10 kg what will be recoil velocity of gun?​

Answer 1

${\rm{\red{\underline{\underline{\huge{Answer}}}}}}$

$\bigstar{\bold{Recoil\:velocity\:=-0.2\:m/s}}$

$\Large{\underline{\underline{\bf{Given:}}}}$

• Mass of bullet (m₂) = 20 g = 0.02 kg
• Velocity of bullet (v₂) = 100 m/s
• Mass of gun (m₁) = 10 kg

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Recoil velocity of gun (v₁)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Recoil velocity of a gun is given by the formula

  v₁ = -m₂v₂/m₁

→ Substituting the given datas we get

  v₁ = -(0.02 × 100)/10

  v₁ = -0.2 m/s

$\boxed{\bold{Recoil\:velocity\:=-0.2\:m/s}}$

Here recoil velocity is negative since the direction of the bullet is opposite to that of the gun.

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ Momentum is always conserved in an isolated system. That is the momentum before collissio is equal to the momentum after collission.

Thanks!

Answer 2

Answer:

{\rm{\red{\underline{\underline{\huge{Answer}}}}}}

Answer

\bigstar{\bold{Recoil\:velocity\:=-0.2\:m/s}}★Recoilvelocity=−0.2m/s

\Large{\underline{\underline{\bf{Given:}}}}

Given:

Mass of bullet (m₂) = 20 g = 0.02 kg

Velocity of bullet (v₂) = 100 m/s

Mass of gun (m₁) = 10 kg

\Large{\underline{\underline{\bf{To\:Find:}}}}

ToFind:

• Recoil velocity of gun (v₁)

\Large{\underline{\underline{\bf{Solution:}}}}

Solution:

→ Recoil velocity of a gun is given by the formula

v₁ = -m₂v₂/m₁

→ Substituting the given datas we get

v₁ = -(0.02 × 100)/10

v₁ = -0.2 m/s

\boxed{\bold{Recoil\:velocity\:=-0.2\:m/s}}

Recoilvelocity=−0.2m/s

Here recoil velocity is negative since the direction of the bullet is opposite to that of the gun.

\Large{\underline{\underline{\bf{Notes:}}}}

Notes:

→ Momentum is always conserved in an isolated system. That is the momentum before collissio is equal to the momentum after collission.

Thanks!