Question

A ball of uniform density 2/3 of that of water is
dropped freely into a pond from a height 10 m
above its surface. The maximum depth the ball can
travel in water is


Pls want full ans... ​

Answer 1

Answer:

The maximum depth of a ball can travel in water is 20m (s= 20 m)

Explanation:

Buoyant force is measured as:

Fb = Vpg;

wherein Fb =force that acts on the liquid;

V = Volume of the object that is immersed in the liquid;

p= Density of the liquid;

g= gravitational force

Volume = mass x density

V = m / d

Therefore, converting in above equation;

Fb = m/d x p x g

It is stated that; Fb = 3/2 mpg

Since, p = 1 gm/cm^3 for water

and Fb is 3/2 mg

The resulting force that acts on the ball is:

                   = Fb – Mg

                   = 3/2mg – mg

                   = mg/2 (upward)

Force = m x a;

As determined above;

Mg/2 = m x a;

A = -g/2  

Based on the formula used for potential energy;

U = √2gh

U^2 = 2gh = 2 (10) (10)

       = 200

Then;

V^2 – U^2 = 2 as;

Here V=0;

200=2 (10/2)s

So s= 20 m

Thus, the maximal depth to which the ball travels in 20 m

Answer 2

The answer is given in the below photo. Please refer to that for the solution.