Question

A ball os projected vertically upward with a speed of 30m/s, if it was stopped after 1.5 s and thrown upwards again with a speed of 25m/s, find the time taken to reach back to the ground

Answer 1

Answer:

In second case-

Initial velocity= 25 m/s

Final velocity= 0 ( as it will reach its highest point it's velocity will become zero)

Acceleration due to gravity= -9.8 m/s^2

v = u + gt

=> 0 = 25 + (-9.8) × t

=> 0 = 25 - 9.8t

=> -25 = -9.8t

=> -25/-9.8= t

=> 2.63157895 s or 2.6 s= t

Thus, the time is 2.6 s.

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