A ball ‘P’ of mass 200g is moving towards right with 9m/s while another ball ‘Q’ of mass 300g is moving towards left along same line with 6m/s. These two collide and after collision ‘P’ moves towards left with 6m/s. The balls were in contact for 0.25s with each other while colliding. In this process the ball ‘P’ experiences a force while colliding with ‘Q’. plz solve if u can related q:= The velocity of ball ‘Q’ after collision The force on ball 'P' will be? The momentum of ball P before collision was?
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Answer:
Using the below you can sove that.
Explanation:
Let their velocities after the collision be v
1
and v
2
. As we know for elastic collision.
Relative velocity of approach = relative velocity of separation
10−4=v
2
−v
1
⇒6=v
2
−v
1
⇒v
1
=v
2
−6
Applying conservation of momentum,
10×10+5×4=10v
1
+5v
2
120=10v
1
+5v
2
120=10(v
2
−6)+5v
2
=15v
2
−60
15v
2
=180⇒v
2
=12cm/sec
v
1
=6cm/sec
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