A ball P of mass m moving with a velocity v strikes another ball Q of same mass but at rest. After Collision if 'P' comes to rest find velocity of Q:
Answers
Answered by
2
Answer:
Solution
The correct option is D
p
+
q
p
(
q
−
1
)
Let the mass and velocity of body P be
m
and
v
respectively. So, the mass of body Q is
m
p
and its velocity is
v
q
.
From the principle of conservation of momentum, we have (since body P comes to rest after collision)
m
v
+
m
p
×
v
q
=
m
p
×
v
′
where
v
′
is the velocity of body Q after the collision.
Solving we get,
v
′
=
v
(
p
+
q
p
q
)
Now, the coefficient of restitution is given by
e
=
v
′
v
−
v
q
=
p
+
q
p
(
q
−
1
)
Answered by
0
Answer:
velocity of ball Q will be v
Explanation:
This question is solved using third law of motion
conservation of momentum
initial momentum = final momentum
m1v + m2(0) = m1(0) + m2(v2)
m1 =m2
mv=mv2
v2=v
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