Question

a ball projected at an angle 45 degree horizontally with the velocity 50 m/s then find horizontal and vertical velocity.​

Answer 1

Answer:

t= u (sinA−cosA)

_

g

at time

′

t

′

V

y

=V

x

=u

x

=ucosα

⇒ucosα=usinα−gt

gt=u(sinα−cosα)

t=

g

u(sinα−cosα)

Answer 2

horizental and vertically velocity bcx fornulais ui multiply cos 45° and vertically ui Multiply sin45°for both 35.35 m/sec