A ball projected from ground vertically upwards is at same height at t1 and t2 . The speed of projection of the ball is [ Neglect the effect of air resistance ]
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Let us say, the ball take Δt
time to reach at to most point 3 from point 1
The ball will take time Δt again to reach from portion 3 to portion 2
⇒ t
1
Δt+Δt=t
2
⇒ t
1
+2Δt=t
2
⇒ Δt=
2
t
2
−t
1
Let the projected speed of ball be it at position 3 the speed of ball =0
Applying I equation of motion
o=v−g(t
1
+Δt)
⇒ v=g(t
1
+Δt)
v=g(t
1
+
2
t
2
−t
1
)
⇒ v=g
2
(t
1
+t
2
)
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