Question

a ball projected horizontally with velocity of 5m/s from the top of the building 19.6m high how long will ball take hit the ground

Answer 1

give velocity= 5m/s hight = 19.6m so the time required by the ball to hit the groud will be = 3.92 s

Answer 2

Answer:

The time is 2 sec.

Explanation:

Given that,

Velocity = 5 m/s

Height = 19.6 m

We need to calculate the time

Using equation of motion

$s=ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$19.6=0+\dfrac{1}{2}\times9.8\times t^2$

$t^2=\dfrac{19.6}{4.9}$

$t=\sqrt{\dfrac{19.6}{4.9}}$

$t=2\ sec$

Hence, The time is 2 sec.