A ball projected in a projectile motion with velocity of 20ms-¹. If the time required by the ball to reach maximum height is 5s. Calculate the horizontal range covered by the ball
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the distance covered by the ball is equals to square of the velocity into sin 2 theta divided by the gravity
time taken by the ball is equals to 2 into velocity into sin theta divided by g
substituting the values and eliminating science gives you the range.
time taken by the ball is equals to 2 into velocity into sin theta divided by g
substituting the values and eliminating science gives you the range.
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