Question

A ball projected up an incline plane; travels the first 10 metre in 1 second and the next 10 metre in 5/2 second how much further will it travel be force it comes to rest​

Answer 1

Answer:

The velocity of the projection of the ball on the inclined force u=10m/s

The angle of edge of projection with the ball on edge of the slope α=30

The effective acceleration due to gravity towards the bottom edge will be gsinθ considering the angle of inclination of the slope is θ and acceleration due to gravity g=10m/s

2

The net displacement of the ball along the normal to the bottom edge of the inclined plane during its motion not t=2 sec on the inclined force is = zero

Hence by applying equation of the kinematics we can write

θ=O=usin30

0

×t−

2

1

gsinθ×t

2

or, O=10sin30

0

×2−

2

1

×10×sinθ×2

2

or, sinθ=sin30

0

or, θ=30

0

.

Step-by-step explanation:

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