A ball projected upwards from the top of a tower with velocity 50ms-1 making an angle if 30' with horizontal .the height of tower is 70m.after how much time from the instant of throwing with the ball reach the ground
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hi,
hope this helps you.
Let throwing point be (0,0). Horizontal be x-direction and vertical be y-direction
Initial velocity = (50cos30) i + (50sin30) j,a = -10 js = ut + 0.5*a*t2, s = (50*cos30*t) i + (50*sin30*t – 5*t2) j, it will reach the ground when y-coordinate of ball is -70,So, (50sin30*t – 5t2) = -70or, 25*t-5*t2=-70, t2-5t-14=0(t-7)(t+2)=0 => t=7
thank you.
hope this helps you.
Let throwing point be (0,0). Horizontal be x-direction and vertical be y-direction
Initial velocity = (50cos30) i + (50sin30) j,a = -10 js = ut + 0.5*a*t2, s = (50*cos30*t) i + (50*sin30*t – 5*t2) j, it will reach the ground when y-coordinate of ball is -70,So, (50sin30*t – 5t2) = -70or, 25*t-5*t2=-70, t2-5t-14=0(t-7)(t+2)=0 => t=7
thank you.
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