A ball projected vertically upwards from the top of a tower with a velocity 20m/sec. reaches the ground in t¹ sec. . if it is projected vertically downwards from the top with the same velocity, it reaches the ground in t² seconds Relationship between t¹ and t² will be:
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We know, v 2 =u 2 −2gsv=0 for maximum height.Since g is constant, s∝u 2 .So, s 2 s 1 =( u 2 u 1 ) 2 u 1 =20m/s, u 2 =40m/s, s 1 =20ms 2 =( 2040 ) 2 ×20=4×20=80 m PLZ MARK ME AS BRAINLIEST ANSWER
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