Question

A ball projected with K:E E at angle of 45to the horizontal .At the height point during its flight its K:E will be????​

Answer 1

Answer :

Angle of projection = 45°

Kinetic energy at initial point = E

We have to find kinetic energy of ball at highest point$.$

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◈ Let a ball of mass m is projected at initial speed of u.

Kinetic energy at initial point :

➝ Ki = 1/2 mu²

ATQ, Ki = E

Therefore, 1/2 mu² = E

Speed at highest point = u cosΦ

Kinetic energy at highest point :

➝ K = 1/2 m(u cosΦ)²

➝ K = 1/2 mu² × cos²45°

➝ K = (E) × (1/√2)²

➝ K = E/2

Hence, Kinetic energy of ball at highest point will be E/2.