Question

A ball reaches a racket at 60 m/s along + x direction and leaves the racket in the opposite direction with the same speed assuming that the mass of the ball as 50 gm and the contact time is 0.02 second the force required by the racket on the ball is

Answer 1

here acceleration is.( v + u ) / t. this is because the final velocity is in the opposite direction


so. a = 60 + 60 divided by 0.02 that will be 6000 M per second square

so the force applied on the ball would be mass into the particular acceleration so as the masses in grams we have to

convert it first into kgs

so that will be 0.05 kgs

so now multiply 0.05 into 6000

that will be 300 Newtons


if helped please mark BRAINLIEST

Answer 2

Explanation:

60 + 60 equal to 120 song song the acceleration equal to 120 and when you multiply 0.05 into 0.02 into the 60 + 60 you get answer 310 along X direction because the direction