Question

a ball reaches erakat at 60 metre per second along + X direction and leaves the racket in the opposite direction with the same speed assume that the mass of the ball as 50 grams and the contact time is 0.02 second the force exerted by the racket on the bowlers ​

Answer 1

Explanation:

Here acceleration is.( v + u ) / t. this is because the final velocity is in the opposite direction

so. a = 60 + 60 divided by 0.02 that will be 6000 M per second square

so the force applied on the ball would be mass into the particular acceleration so as the masses in grams we have to

convert it first into kgs

so that will be 0.05 kgs

so now multiply 0.05 into 6000

that will be 300 Newtons