Question

A ball released from a height falls 5 m in one second. In 4 seconds it falls through​

Answer 1

Answer:

80 m

Step-by-step explanation:

AS s = ut + 1/2 gt^2 where u is initial velocity & a is acceleration.

ATQ : u=0 & a=g

So, distance travelled in 4 sec is,

s = 1/2 * 10 * 16

s 80 m.

Answer 2

Answer = 80m

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