Question

A ball released from a height 'h' touches the ground in 'ť s. The height of the body from the ground after t/2 seconds is​

Answer 1

Answer: 3h/4  

​

Step-by-step explanation:

Let h  

1

​

 be the height from the body after release from the top position.

So, we know that, S= gt2/2

 

​

 

So, for t second of time, h=  

2  

 

​

 

And for  

2

t

​

 second of time

h  

1

​

=  

2

g(t/2)  

2

 

​

 

Taking ratio of h and h  

1

​

,we find the distance travelled from top point.

h  

1

​

 

h

​

=4

⇒h  

1

​

=  

4

h

​

 

Now from bottom total height will be: h−  

4

h

​

=  

4

3h

​