Question

A ball released from a height h touches the ground in 't' sec. Ater t/2 sec since dropping, the height of the body from the Xh ground 4. Then find the value of X?
​

Answer 1

Answer:

Let h  

1

​

 be the height from the body after release from the top position.

So, we know that, S=  

2

gt  

2

 

​

 

So, for t second of time, h=  

2

gt  

2

 

​

 

And for  

2

t

​

 second of time

h  

1

​

=  

2

g(t/2)  

2

 

​

 

Taking ratio of h and h  

1

​

,we find the distance travelled from top point.

h  

1

​

 

h

​

=4

⇒h  /1

​

=  

4 /h

​

 

Now from bottom total height will be: h−  

4 /h

​

=  

4 /3h

​

Explanation: