A ball released from a top of tower of height h meter it takes t seconds to reach the ground what is position of ball inn t/4 seconds
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h=ut +1/2gt^2 then if t is T/4 then H =ut +1/2g .t/4^2 h=H/16 then position of ball in t/4 second is H/16 from top of tower means H-H/16=15H/16 from ground
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Answer:
h= ut*1/2gt^2
answer is 15h/6
Explanation:
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